Polar Graph Art Equations by Asun Phong

Science is Beauty • Polar graph art made with the app `Quick Graph´… A...

Web developer and graphic designer Asun Phong creates these polar graph art equations with the app `Quick Graph´.
“I got this handy app on my phone called ‘Quick Graph’ which seems to work quite well for sketching polar graph art equations. It’s not as powerful by any means as Mac Grapher, but it works well for experimenting with different mathematical shape dynamics. Here are some designs produced waiting for the bus over the past few weeks. Images were run off the smart phone through Instragram.”Phong

Website

r=2
r=6-ceil(abs(cos(Θ⋅1)^2⋅2)⋅2)
r=6+ceil(abs(cos(Θ⋅1)^2⋅2)⋅2)
r=7+ceil(abs(cos(Θ⋅1)^2⋅2)⋅2)+abs(tan(Θ))
r=8+ceil(abs(cos(Θ⋅1)^2⋅2)⋅2)+abs(tan(Θ))+abs(tan(Θ+π/2))
r=8-ceil(abs(cos(Θ⋅1)⋅2)⋅2)+min(ceil(abs(tan(Θ⋅1)⋅0.3)),6)
r=10+ceil(abs(cos(Θ⋅1)^2⋅2)⋅2)+abs(tan(Θ))+abs(tan(Θ+π/2))+abs(tan(Θ⋅8))

r=0.3
r=\mbox{ceil}\left( \mbox{abs}\left( \cos \left( \theta \cdot 2 \right)^{2}\cdot 2 \right) \right)\cdot .6-\min \left( \cos \left( \theta \cdot 2 \right)^{256},0.4 \right)
r=0.25+\cos \left( \theta \cdot 2 \right)^{2}+\frac{\mbox{ceil}\left( \left( \mbox{abs}\left( \cos \left( \theta \cdot 4+\frac{\pi }{2} \right) \right)\cdot 2 \right) \right)}{2}+\min \left( \left( \cos \left( \theta \cdot 2 \right)^{512} \right),0.8 \right)
r=1.75+\cos \left( \theta \cdot 2 \right)^{2}+\frac{\mbox{ceil}\left( \mbox{abs}\left( \cos \left( \theta \cdot 4+\frac{\pi }{2} \right) \right)\cdot 2 \right)}{4}\cdot \mbox{abs}\left( \tan \left( \theta \cdot 16 \right) \right)

r=2+cos(Θ⋅6+π)
r=4+cos(Θ⋅6)
r=6+cos(Θ⋅6+π)
r=8+cos(Θ⋅6)
r=10+cos(Θ⋅6+π)
r=11
r=1
r=11.5+(cos(Θ⋅6)⋅0.99)⋅0.5
r=12
r=14+ceil(abs(cos(Θ⋅6)^1)⋅2)
r=13+ceil(abs(cos(Θ⋅6)^3)⋅2)
r=12+ceil(abs(cos(Θ⋅6)^16)⋅2)
r=18-ceil(abs(cos(Θ⋅6+π)^16)⋅2)

r=0.5
r=3-abs(cos(Θ⋅5+π/1))⋅2
r=6-min(abs(tan(Θ⋅5+π/1))/10,3)
r=8-min(abs(tan(Θ⋅1+π/1))/20,5)
r=10+min(abs(tan(Θ⋅1+π/1))/10,3)
r=16-min(abs(tan(Θ⋅1+π/1))/10,3)
r=22-min(abs(tan(Θ⋅1+π/1))/10,9)
r=7-min(abs(tan(Θ⋅1+π/1))/20,3)+sin(Θ⋅20-π/2)⋅0.5
r=max(22+abs(tan(Θ⋅20)^2),22)-min(abs(tan(Θ⋅1+π/1))/10,9)

r=2
r=max(0.5+ceil(abs(tan(Θ⋅3)^3⋅5)),15)+ceil(cos(Θ⋅3+π/2)^9⋅1)⋅1.5
r=ceil(abs(cos(Θ⋅3+π/2)^4)⋅2)⋅2+10+cos(Θ⋅3+π/2)⋅1.5+cos(Θ⋅3+π/2)^2+abs(tan(Θ⋅1.5-π/4))^3
r=ceil(abs(cos(Θ⋅1.5-π/4)^3)⋅3)+1
r=ceil(abs(cos(Θ⋅1.5+π/4))⋅2)⋅3
r=7.3+ceil(abs(sin(Θ⋅1.5-π/4)^5⋅2.0))-ceil(abs(sin(Θ⋅1.5+π/4)^24⋅2.0))+cos(Θ⋅3+π/2)^9
r=9.5+abs(ceil(cos(Θ⋅3+π/2)^3⋅1.99))+cos(Θ⋅3+π/2)⋅1.5+cos(Θ⋅3+π/2)^2+abs(tan(Θ⋅1.5-π/4))/10

r=2+(((abs(cos(Θ⋅3)))+(0.25-(abs(cos(Θ⋅3+π/2))))⋅2)/(2+abs(cos(Θ⋅6+π/2))⋅8))
r=3+(((abs(cos(Θ⋅6)))+(0.25-(abs(cos(Θ⋅6+π/2))))⋅2)/(2+abs(cos(Θ⋅12+π/2))⋅8))
r=1+(((abs(cos(Θ⋅3)))+(0.25-(abs(cos(Θ⋅3+π/2))))⋅2)/(2+abs(cos(Θ⋅6+π/2))⋅8))

r=2
r=8+ceil((abs(cos(Θ⋅2))⋅3))
r=4+ceil(abs(cos(Θ)⋅3))
r=12+ceil(abs(cos(Θ⋅4+π/2)⋅3))
r=16+ceil(abs(cos(Θ⋅8)⋅2))
r=18+ceil(abs(cos(Θ⋅16)⋅2))
r=20+ceil(abs(cos(Θ⋅16+π/2)⋅2))+cos(Θ⋅16)

via [ScienceIsBeauty]

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3 Responses to Polar Graph Art Equations by Asun Phong

  1. Anonymous says:

    Hi my name is gimmy

    Like

  2. Michael Brandau says:

    I tried to graph these on desmos but it’s showing the whole thing. I think there are missing equations for some of them. Please fix.

    Like

  3. Michael Brandau says:

    not showing the whole thing. My bad

    Like

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